<span>Have you considered calculating it directly? $2,962.40*(0.06/12)
If you do that then your answer would be 14.81...
Hope this helps... :)</span>
Answer:
First translation (-3, 3) second translation (3, 3)
Step-by-step explanation:
Answer:
Number of families will have both radio and television = 44
Step-by-step explanation:
Given:
Number of family have radio = 794
Number of family have TV = 187
Number of family haven't both = 63
Find:
Number of families will have both radio and television
Computation:
Number of families will have Tv or radio = 1,000 - 63
Number of families will have Tv or radio = 937
Number of family have one of them = 794 + 187
Number of family have one of them = 981
Number of families will have both radio and television = 981 - 937
Number of families will have both radio and television = 44
The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%
<h3>What is Probability ?</h3>
Probability is defined as the likeliness of an event to happen.
Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.
It is given that
X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ) of 10.8 lb.
Population Mean (μ) = 2.1
Population Standard Deviation (σ) = 10.8
We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:
Then the probability is given as
Pr(X≥15)=0.1162. (11.6%)
The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%
To know more about Probability
brainly.com/question/11234923
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Answer:
36+30 = 6(6+5)
Step-by-step explanation:
We just simply expand the brackets:
6×6=36
6×5=30
30+36=76
so 76-36=30
So the missing number was 30