The calorimetry experiment is usually done to determine the heat capacity of the sample. The working equation would be:
Q = mCpΔT
Q is the energy
m is the mass of sample
Cp is the heat capacity
ΔT is the temperature
So, if the thermometer is too high, then that would affect ΔT, which would make it greater. Consequently, you would calculate a much lesser heat capacity of the sample compared to the theoretical value.
Answer:
It increases when the temperature increases.
Explanation:
- According to Arrhenius relation: k = Ae(-Ea/RT).
- The rate constant of the reaction and also the rate of the reaction increases exponentially with increasing the temperature of the reaction.
- As the temperature increases, the no. of molecules that can posses the critical energy (activation energy) to initiate the chemical reaction and pass the energy barrier increases.
Answer:
15000N/m²
Explanation:
Given parameters:
Force exerted by the girl = 450N
Area = 300cm²
Unknown:
Pressure exerted by her feet =?
Solution:
Pressure is the force per unit area on a body;
Pressure =
We need to convert the given area to m²;
10000cm² = 1m²
300cm² = = 0.03m²
Pressure = = 15000N/m²
Chemical Change because if it would be a physical change the physic of the tea would look different but it doesn’t
Answer:
6.1×10^8
Explanation:
The reaction is;
Sn^2+(aq) + Cd(s) -----> Sn(s) + Cd^2+(aq)
E°cell = E°cathode - E°anode
E°cathode= -0.14 V
E°anode= -0.40 V
E°cell = -0.14-(-0.40)
E°cell= -0.14+0.40
E°cell= 0.26 V
But
E°cell= 0.0592/n log K
E°cell= 0.0592/2 log K
0.26= 0.0296log K
log K = 0.26/0.0296
log K= 8.7838
K= Antilog (8.7838)
K= 6.1×10^8