Answer:
The water level is dropping at a rate of 0.24 ft/s
Step-by-step explanation:
Here, we simply want to calculate the change in depth (height of the cone) , given the volume change
Mathematically, we have the volume of a cone as;
V = 1/3 * π * r^2 * h
we are given dv/dt as 12 ft^3/m
dv/dh = 1/3 * π * r^2
Substituting the value for the radius, we have
dv/dh = 1/3 * 22/7 * 4^2 = 50.29
dh/dt = dh/dv * dv/dt
dh/dv = 1/(dv/dh) = 1/50.29
Thus,
dh/dt = 1/50.29 * 12
dh/dt = 0.24 ft/s
A' (. -4+3,-3+2). A' ( -1,5)
B' ( 2,3)
C' ( 6,7)
D' ( 5,-3)
Answer:
The coordinates of J are missing. Plus, I don't see options for the conclusions. I made an imaginary point J, which you could correct to form the proper triangle.
Step-by-step explanation:
See the attachment. Plot all the vertices, including a corrected point J and draw the resulting triangle. It might be that AJKL is a slightly smaller, shifted version of AGHI. Enter the correct coordinates and then compare.
Answer:
D: 8
Step-by-step explanation:
7 + (2 + 6) ^2 ÷ 4 ⋅ (1/2)^4
According to PEMDAS
We to parentheses first
7 + (8)^ 2 ÷ 4 ⋅ (1/2)^4
Then we do exponents
7 + 64 ÷ 4 ⋅ (1/16)
The multiply and divide from left to right
7+64 ÷ 4 ⋅ (1/16)
7+16 ⋅ (1/16)
Then add and subtract from left to right
7+1
8
Answer:
A
Step-by-step explanation:
