The summand (R?) is missing, but we can always come up with another one.
Divide the interval [0, 1] into 
subintervals of equal length 
:
![[0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right]](https://tex.z-dn.net/?f=%5B0%2C1%5D%3D%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%5Ccup%5Ccdots%5Ccup%5Cleft%5B1-%5Cdfrac1n%2C1%5Cright%5D)
Let's consider a left-endpoint sum, so that we take values of 
where 
is given by the sequence
with 
. Then the definite integral is equal to the Riemann sum
Answer:
12.53
Step-by-step explanation:
6^2+11^2=sqrt157 =12.53
Answer:
7 bucks
Step-by-step explanation:
x*.8=5.62
divide both sides by .8
x=7
Let the number be x. The other number is also x.
Given the first number is 24.6 and sum is -44.85
24.6 + x + x = -44.85
Combine like terms:
2x + 24.6 = -44.85
Add 24.6 on both sides:
2x = -44.85 - 24.6
Evaluate Right Hand Side:
2x = -69.45
Divide both sides by 2:
x =- 34.725
Answer: The two numbers are both -34.725.
6xn+n-11 so n=6
6x6=36+6=42-11 is 31
