Answer:
7 yards
Step-by-step explanation:
gained 6 yards on a first down +6
lost 15 yards on the second down - 15
gained 12 yards on the third down +12
At the end of the third down
+6 -15+12 = +3
They want to have a 10 yard gain at the end of the 4th down
+3 + x = +10
Subtract 3 from each side
+3-3 +x = +10-3
x = 7
They need to gain 7 yards
All you gotta do is pick a random point on the x-axis, lets say, x=2 in this case, and plug it into the equation.
If x=2, y = (1/2)2 - 3 = 2 - 3 = -1
When x = 2, y = -1
Now pick another point, x = 1
x = 1, y = (1/2)1 - 3 = 0.5 - 3 = - 2.5
When x = 1, y = - 2.5
Draw a cross on those 2 points, on the 2d plane
(1, -2.5) and (2, -1)
and draw a line between them, and make the line continue past the points, having no boundaries but the paper you hold, keeping it straight the entire time. With not turns.
If you want to draw out a table, make it have 2 rows, and 6 columns.
Write x in the first column of the first row, and write y in the first column of the second row.
Now, write down a different, random x value, in each column in the first row.
In the second row, in each column, write the y value, that corresponds to the x value given above each individual column, based on the equation
y = 1/2x - 3.
Answer:
x = -0.35
Step-by-step explanation:
tep 1 - Multiply 64 and 0.5x. The answer ends up being 32x
Step 2 - You need to get all of the variables on one side and the regular numbers on the other side. To do that, you need to subtract 2.5x from each side so you are left with the equation -10.5 = 29.5x
Step 3 - The final step is to isolate the variable. To do this, you divide each side by 29.5 meaning that x = -0.35
Answer:
f(g(-8)) = -26
Step-by-step explanation:
Given:
f(x)=2x and g(x)=2x+3
Required:
f(g(-8))=?
Solution:
First we will find g(-8)
g(x) = 2x+3
g(-8)= 2(-8)+3
= -16 + 3
= -13.
so, g(-8) = -13
Now, for calculation f(g(-8)) we can put the value of g(-8) i.e, -13
so, f(x) = 2x
f(-13) = 2(-13)
= -26
so, f(-13) = -26
and f(g(-8)) = -26
Parallel lines are both vertical and they don’t meet.