Answer:We know the total amount of money invested. $17818
x+y=17818,
We know that the difference in interest earned by the two accounts is $490.33
0.11*x-0.06*y=490.33
x=17818-y
We substitute for x
0.11*(17818-y)-0.06*y=490.33
We multiply out
1959.98-0.11y-0.06*y=490.33
We combine like terms.
1469.65=0.17*y
Isolate y
y=1469.65/0.17
y=8645 at 6%
Calculate x
x=17818-8645
x=9173 at 11%
Check
0.11*9173-0.06*8645=490.33
interest earned at 11%=1009.03
interest earned at 6%=518.70
1009.03-518.7=490.33
490.33=490.33
Since this statement is TRUE and neither amount is negative then all is well.We know the total amount of money invested. $17818
x+y=17818,
We know that the difference in interest earned by the two accounts is $490.33
0.11*x-0.06*y=490.33
x=17818-y
We substitute for x
0.11*(17818-y)-0.06*y=490.33
We multiply out
1959.98-0.11y-0.06*y=490.33
We combine like terms.
1469.65=0.17*y
Isolate y
y=1469.65/0.17
y=8645 at 6%
Calculate x
x=17818-8645
x=9173 at 11%
Check
0.11*9173-0.06*8645=490.33
interest earned at 11%=1009.03
interest earned at 6%=518.70
1009.03-518.7=490.33
490.33=490.33
Since this statement is TRUE and neither amount is negative then all is well.
Answer:
it looks great! i'd give you an a+
honestly I couldn't make that
Answer:
The linear relationship ( the linear equation ):
y = m x + b ( the slope-intercept form )
m = ( 50.75 - 42.25 ) / ( 5 - 3 ) = 8.50 / 2 = 4.25 ( the slope )
42.25 = 4.25 * 3 + b
b = 42.25 - 12.75
b = 29.50
y = 4.25 * x + 29.50
Answer:
The initial value is : ( 0, 29.50 ) or 29.50.
To determine the number of cars that will be sold by the year 2020, we will use the equation,
N = (N1)(1 - r)^(t)
where N1 is the starting number of cars, r is the rate of the decrease, and t is the number of years from 2012. Substituting the konwn values,
N = (500)(1 - 0.028)^(8)
N = 398.38
The closest integer to the calculated value is 398. Thus, the answer is 398 cars.