The strategy for winning every time appears to be to ensure that the remaining number of coins is a multiple of 6. Then the first player can ensure a win by taking 2 coins to make the total number be 48.
2m + 3b + c + h m = 8.99, b = 7.47, c = 2.99, h = 29.99 2(8.99) + 3(7.47) + 2.99 + 29.99 17.98 + 22.41 + 2.99 + 29.99 the answer is $73.37 before sales tax