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2 years ago

How many grams of nickel metal are plated out when a constant current of 15.0 Ais passed through aqueous NICl2 for 80.0 minutes?

Physics

1 answer:

Alika [10]2 years ago

3 0

Answer:

21.89 g

Explanation:

i = 15 A

time = 80 minutes = 80 x 60 = 4800 second

Electro chemical equivalent of nickel, Z = 0.000304 gram per ampere second

Use the Faraday's law of electrolysis

m = z i t

where, m is the mass deposited, i be the current, z be the electro chemical equivalent and t be the time taken

m = 0.000304 x 15 x 4800

m = 21.89 g

Thus, the mass f nickel deposited is 21.89 g.

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2 years ago

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Explanation:

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2 years ago

In a semiclassical model of the hydrogen atom, the electron orbits the proton at a distance of 0.053 nm. Part A What is the elec

Bezzdna [24]

Answer with Explanation:

We are given that

$r=0.053 nm=0.053\times 10^{-9} m$

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a.We have to find the electric potential of the proton at the position of the electron.

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$V=\frac{kq}{r}$

Where $k=9\times 10^9$

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$V=27.17 V$

B.Potential energy of electron,U= $\frac{kq_e q_p}{r}$

Where

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$q_p=q=1.6\times 10^{-19} C$ =Charge on proton

Using the formula

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2 years ago

15 Points , Physics HW, can someone please show me step by step how to calculate percent difference for this problem. My numbers

timofeeve [1]

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$\dfrac{|y-x|}x \times 100\%$

The absolute value is there because we only care about the absolute percent difference, and not taking into account whether we go from $x$ to $y$ or vice versa. If we remove them, we have two possible interpretations of percent difference.

For example, the (absolute) percent difference between 3 and 6 is

$\dfrac{|6-3|}3 \times 100\% = 100\%$

In other words, we add 100% of 3 to 3 to end up with 6. This is the same as the percent difference going from 3 to 6. On the other hand, the percent difference going from 6 to 3 is

$\dfrac{3-6}3\times100\%=-50\%$

which is to say, we take away 50% of 6 away from 6 to end up with 3.

"Make comparisons to object measurements" tells us that the differences should be computed relative to "measurements for object". In other words, take $x$ from the left column and $y$ from the right column.

$\dfrac{|7.1-7.3|}{7.1} \times 100\% \approx 2.82\%$

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1 year ago

Directions: Read the following excerpts carefully, then identify whether they employ informative, persuasive, or argumentative w

Savatey [412]

Hi there!

Informative writing has the intent to inform or educate us on a particular topic or event. It gives us more information and insight onto something.

Persuasive writing has the intent of convincing us to believe in a certain idea or to perform a certain action. For instance, advertisements have a persuasive intent; they are persuading us to buy a product or service.

Argumentative writing is similar to persuasive writing in the sense that they are persuading us to believe a certain idea. However, they are often based on logic and fact rather than opinions.

Let's look at the first excerpt.

<em>This morning at 9 a.m., a school bus collided with a car at the intersection of Osmena and Cabrera streets. The passengers were not injured, but the medical personnel checked each student as well as the driver before they were transported to their school.</em>

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Therefore, this excerpt uses an informative writing technique.

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1 year ago