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2 years ago

7

This math question is hard. Help Me Pls

1 answer:

devlian [24]2 years ago

6 0

Answer:

solution is: plus -2

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a ladder 13m long is placed on the ground in such a way that it touches the top of a vertical wall 12m high. find the distance o

Sergio039 [100]

Answer:

by applying Pythagoras theorem;

the ladder(13m) acts as hypotenuse

the wall (12m) acts as height

the distance between the the two is the base

therefore

a² + b² = c²

b²= c²- a²

b²= 169 - 144

b² = 25

√b² = √25

b= 5m

the distance is 5m

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2 years ago

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Norma-Jean [14]

You’re answer should be 9-7 hope this helped

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Cerrena [4.2K]

Answer:

747

Step-by-step explanation:

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1 year ago

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Can anyone help me with this problem

Anit [1.1K]

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2 years ago

Tara ran the 1600 M event at a constant speed in 5 minutes and 20 seconds. what was her speed

ollegr [7]

5 m/sec or 300m / min

using speed = $\frac{distance}{time}$

change 5 min 20 sec to seconds = (5 × 60) + 20 = 320 sec

speed = $\frac{1600}{320}$ = 5m / second or

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2 years ago