6(x-7)=10(x+4)
6x-42=10x+40
-42-40=10x-6x
-82=4x
x=-20.5 done.
In order to solve for parallel, perpendicular, or neither, you have to look at the slope.
If the slope is the same for both equations, it is most likely parallel.
If it's the reciprocal (Where you flip the number and add change the signs. For example, the reciprocal of 1/2 is -2)
If the slope is not the same or the reciprocal, then it is neither.
So for the first equation, your slope is:
3x+2y=6
2y=-3x+6
y=-3/2x+3 The equation y=mx+b can help you here, where m is the slope.
Your slope is -3/2
For the second equation, your slope is -3/2 since y=-3/2x+5 is already in y=mx+b form and m is the slope.
Since both slopes are -3/2, then you have parallel equations!
(Be careful though, sometimes it will have the same slope but there will also be the same y-intercept. If that happens, it's no longer parallel, but it's the same equation. Such as y=-3/2x+1 and y=-3/2x+1. In this case there will be infinite solutions, but parallel equations have no solutions.)
I hope this helps!! Please ask if you have more questions!
I this the answer you are looking for would probably be 47.7%.
hope this helps!!
Recall Euler's theorem: if , then
where is Euler's totient function.
We have - in fact, for any since and share no common divisors - as well as .
Now,
where the are positive integer coefficients from the binomial expansion. By Euler's theorem,
so that
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!