We have two points so we can find the gradient using y1-y2/x1-x2
gradient = 21-27/2-8
= 1
we know the form for any linear equation is y = mx + c
we have m and a point so we can substitute in point (2,21) to find c
21 = 1 x 2 + c
c = 19
therefore, the equation is y = x + 19
I believe the answer would be 1620
The formula for the area of a triangle is (base•height)/2
So 60(54) = 3240/2 = 1620
Please correct me if I am wrong have a good day!
14-10=? less than indicates that a minus sign is needed.
Answer is –4/5
Rearrange the equation to make y the subject
5y = –4x – 35
y = –4/5 x – 7
If the line is parallel to the other line, they both have the same gradients but different y-intercepts, so the gradient is just as is.
Sqrt7 / sqrt 11 = sqrt7/11