Answer:
5.82 mm
Explanation:
length of the track, L = 23 m
Initial temperature, T = 7 °C
final temperature, T' = 30 °C
Coefficient of linear expansion, α = 11 x 10^-6 / °C
Let the increase in length of the track on the hot day is ΔL.
use the formula of the linear expansion
ΔL = L x α x ΔT
ΔL = L x α x (T' - T)
ΔL = 23 x 11 x 10^-6 x (30 - 7)
ΔL = 5.82 x 10^-3 m
ΔL = 5.82 mm
Thus, the increase in the length of the track is 5.82 mm.