The standard form equation of the line connecting the two points is
Linear equation in a standard form is given as
where,
A, B, and C are constants or numbers
x and y are the variables.
To solve this problem, the following steps would be taken:
Step 1: Find the slope of the line connecting points (-3,4) and (2,-6)
where,
Substitute
Step 2: Find the y-intercept (b) of the line by substituting and into (slope-intercept form)
Step 3: Write the equation of the line in slope-intercept form by substituting and into
Step 4: Rewrite the equation in standard form
Add to both sides
The standard form equation of the points (-3,4) and (2,-6) is
Learn more about standard form of two points of a linear equation here:
brainly.com/question/18446164
Answer:
Quadrant 4
Step-by-step explanation:
6 1/8 - (3 3/8 + 2 1/8) =
6 1/8 - (5 4/8) =
5 9/8 - 5 4/8 =
5/8 yds <===
Answer:
Third option
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
x²+2x-15 = x²-3x+5x-15 = x(x-3)+5(x-3)=(x+5)(x-3)
or delta:
∆=2²-4*1*(-15)=4+60=64
√∆=8
x1 = (-2+8)/2 = 3
x2=(-2-8)/2=-5
and 4x+20 = 4(x+5)
The same is (x+5), so it is GCF. answer C