Fun
n=number of nickles
q=number of quarters
d=number of dimes
4 more dmes than nickles, 3 more quarters than dimes
d+4=n
q=3+d
total value is 455 cents
10d+5n+25q=455
divide both sides by 5 to simplify
2d+n+5q=91
now we convert all to one coin
q=3+d and n+4=d
subsitute 3+d for q and n+4 for d
2(n+4)+n+5(3+d)=91
2(n+4)+n+5(3+n+4)=91
2(n+4)+n+5(n+7)=91
2n+8+n+5n+35=91
8n+43=91
minus 43 both sides
8n=48
divide both sides by 8
n=6
sub back
n+4=d
6+4=d
10=d
q=3+d
q=3+10
q=13
6 nickles
10 dimes
13 quarters
Well it all depends on the object you are using but in this case lets say remote control cars. You can have an example like "we drove the car around the building twice. the first time it was -8 than how fast it was supposed to go. the second time it was 9. In which round was the car faster?" I dont think i helped very much but i hope i did
Answer:
infinite solutions
Step-by-step explanation:
3(n+6)≥3n+8
3n+18≥3n+8 (distributive property)
18≥8 (subtracted 3n from both sides)
this will always be true so there are infinite solutions
All you have to do is divide the left side of the ratio by 5 and the right side of the ratio by 7. The one that comes out even on both sides is the correct one.