I think it’s the third one if not I apologize
Answer:
3 7/12 kg
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
Step-by-step explanation:
On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.
Total plant bought = 4 1/2 kg
Strawberry = 1 2/3 kg
Tomato = 1/4 kg
Strawberry + tomato
= 1 2/3 + 1/4
= 5/3 + 1/4
= 20+3/12
= 23/12 kg
Total remaining after Sunday
= Total - used
= 4 1/2 - 23/12
= 9/2 - 23/12
= 54-23/12
= 31/12
= 2 7/12 kg
Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.
Strawberry = 2 × 1 2/3
= 2 × 5/3
= 10/3 kg
Tomato = 1 × 1/4
= 1/4 kg
Total plant needed to feed strawberry two more times and tomato 1 more time
= 10/3 kg + 1/4 kg
= 40+3/12
= 43/12 kg
= 3 7/12 kg
He will need 3 7/12 kg of plant
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
165\15= number of tubs
165 divided by 15 equals the amount of the tubs that he sold.
(I assume the two different name things, isaac&dominic, is a mistake since there isnt any information for Dominic)
<span>Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively.
x * (x+1) = (x+2) * (x+3) - 38
x^2 + x = x^2 + 5x +6-38
x^2 + x = x^2 + 5x - 32
-4x = -32
x=8
The four numbers are 8, 9, 10, and 11
check solution: 8*9=10*11-38
72=110-38
72=72</span>
Answer:
I'm going to paint you a picture in words of what this looks like on paper. We have a train leaving from a point on your paper heading straight west. We have another train leaving from the same point on your paper heading straight east. This is the "opposite directions" that your problem gives you.
Now let's make a table:
distance = rate * time
Train 1
Train 2
We will fill in this table from the info in the problem then refer back to our drawing. It says that one train is traveling 12 mph faster than the other train. We don't know how fast "the other train" is going, so let's call that rate r. If the first train is travelin 12 mph faster, that rate is r + 12. Let's put that into the table
distance = rate * time
Train 1 r
Train 2 (r + 12)
Then it says "after 2 hours", so the time for both trains is 2 hours:
distance = rate * time
Train 1 r * 2
Train 2 (r + 12) * 2
Since distance = rate * time, the distance (or length of the arrow pointing straight west) for Train 1 is 2r. The distance (or length of the arrow pointing straight east) for Train 2 is 2(r + 12) which is 2r + 24. The distance between them (which is also the length of the whole entire arrow) is 232. Thus:
2r + 2r + 24 = 232 and
4r = 208 so
r = 52
This means that Train 1 is traveling 52 mph and Train 2 is traveling 12 miles per hour faster than that at 64 mph
Step-by-step explanation: