It is a bit tedious to write 6 equations, but it is a straightforward process to substitute the given point values into the form provided.
For segment ab. (x1, y1) = (1, 1); (x2, y2) = (3, 4).
... x = 1 + t(3-1)
... y = 1 + t(4-1)
ab = {x=1+2t, y=1+3t}
For segment bc. (x1, y1) = (3, 4); (x2, y2) = (1, 7).
... x = 3 + t(1-3)
... y = 4 + t(7-4)
bc = {x=3-2t, y=4+3t}
For segment ca. (x1, y1) = (1, 7); (x2, y2) = (1, 1).
... x = 1 + t(1-1)
... y = 7 + t(1-7)
ca = {x=1, y=7-6t}
Answer:
Latoya's statement because they are similar not congruent
<span>Table
Bottles Price($)
3 78
6 156
9 234
From that you can find the unit price: 78 / 3 = 156 / 6 = 234 / 9 = 26.
That means that the unit rate of this fragance is $26.
If you call x the number of bottles the equation is
Price = unit rate * number of bottles = 26x.
Now compare this information with that on your graph to compare the unit rates.
This can help you fo find the unit rate in from your grpah: the unit rate is the slope of the line =
[change in y-coordinate] / [change in the x-coordinate]
</span>
Answer:
The constant value (often written k) relating amounts that rise or fall uniformly together. It is the ratio of the amounts y and x: k = y/x. Put another way: y = kx.