Since PQ bisects CX at point J, JX=CJ
4y=y+9
-y -y
3y=9
divide by 3
y=3
4p - 2 when p=8
(4 x 8) - 2
32 - 2
30
answer: 30
hope it helped :)
Answer: 0.98630136986
Step-by-step explanation:
There are 365 possible birthdays. The key to assigning the probability is to think in terms of complements: “Two (or more) people share a birthday” is the complement of “All people in the group have different birthdays.” Each probability is 1 minus the other. What is the probability that any two people have different birthdays? The first person could have any birthday (p = 365÷365 = 1), and the second person could then have any of the other 364 birthdays (p = 364÷365). Multiply those two and you have about 0.9973 as the probability that any two people have different birthdays, or 1−0.9973 = 0.0027 as the probability that they have the same birthday. If you have a group of five, it would mean your equation would have to be (p=360÷365)
Answer:
option A
A(-2,-3)
Step-by-step explanation:
make y subject of formula
x+2y=-8
2y=-8-x
y=(-8-x)/2
y=-4-x/2
when x=-2
y=-4-(-2)/2
=-4-(-1)
=-4+1
=-3
(-2,-3) is an ordered pair
