Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
x= 31/5 (Exact form)
x= 6.2 (Decimal Form)
x= 6 1/5 (Mixed number form)
Step-by-step explanation:
Answer:
it will be 1 : 3
Step-by-step explanation:
A long time honestly.
roughly around 4 hours i would think
A I got 850 I multiplied 17 x15 and divided by 2 then multiplied by 29 then divided by 3