You would start off by finding the base, which is 18*12. That equals 216 meters squared, you multiply that by 2 to get the surface area of your 2 bases. That equals 432 meters squared. To find the surface area of the sides (on the left and right side), you would use the equation length times height. To plug in the numbers, you use 12*4, that is 48 meters squared. There are 2 sides, so multiply by 2, to get 96 meters squared. To find the last side, you take length times width, plug in the numbers. Those numbers are 4*18, which equals 72 meters squared. Once again, there are two sides, so you multiply by 2, to get 144 meters squared. Next, as the final step, you add up all of the final numbers. They are: 432+96+144 which equals 672 meters squared.
Your final answer is 672 meters squared.
I hope this helps!
About 6 inches. Originally 5.906 in...
Answer:
If f(1)=0 then 1 is a root and (x-1) is a factor of f(x). divide f(x) by (x-1). you now have a quadratic. Find its roots by methods you know.
actually this factors by grouping:
f(x)=x³+3x²-x-3
= x²(x+3)-1(x+3)
=(x+3)(x²-1)
=(x+3)(x-1)(x+1) // difference of squares
By zero product property roots are
-3, -1, 1
The work required to stretch the spring is 350J.
<h3>Hooke's Law</h3>
This law can be written by the formula: F=kx, where:
F= elastic force (N)
k= spring constant (N/m)
x= linear displacement (m)
<h3>Spring Work</h3>
For finding the spring work in J, you should apply the formula , where:
W= work (J)
k= spring constant (N/m)
x= difference between the linear displacements (m)
The question gives:
x=5 cm=0.05m requires a force of 1.4N
x=8 cm =0.08m
- Step 1 - First, you should find the spring constant from Hooke's law, for x=5 cm and F=1.4N.
- Step 2 - Now you can apply the formula for spring work.
Read more about the spring work here:
brainly.com/question/3317535
N goes one space away from the line if you reflect over the x axis.
M is three spaces away from the line.
A is two spaces..
and the last letter (which I can't see) is 5 spaces away.