You want to know the factor by which 3 2/3 is multiplied to get 7 1/3.
1. You can estimate that it is 2 from 7/3 ≈ 2, then check by multiplication to see if that is right.
.. 2*(3 2/3) = 6 4/3 = 7 1/3 . . . . 2 is the correct factor.
2. You can divide 7 1/3 by 3 2/3 to see what the factor is.
.. (7 1/3)/(3 2/3) = (22/3)/(11/3) = 22/11 = 2 . . . . 2 is the factor Earl used.
3. You could see how many times you can subtract 3 2/3 from 7 1/3.
.. 7 1/3 -3 2/3 = (7 -3) +(1/3 -2/3) = 4 -1/3 = 3 2/3 . . . . . subtracting once gives 3 2/3
.. 3 2/3 -3 2/3 = 0 . . . . . . subtracting twice gives 0, so the factor is 2.
4. You could add 3 2/3 to see how many times it takes to get 7 1/3.
.. 3 2/3 +3 2/3 = (3 +3) +(2/3 +2/3) = 6 +4/3 = 7 1/3
We only need to add two values of 3 2/3 to get 7 1/3, so the factor is 2.
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We have shown methods using multiplication, division, subtraction, addition. Take your pick.
Answer:
15
Step-by-step explanation:
The formula for factoring a sum of cubes is:
We have a=3f and b=5g here.
So a*b in this case is 3f*5g=15fg.
The ? is 15.
Answer:
hi
Step-by-step explanation:
Answer:
c. m∠1 + m∠6 = m∠4 + m∠6
Step-by-step explanation:
Given: The lines l and m are parallel lines.
The parallel lines cut two transverse lines. Here we can use the properties of transverse and find the incorrect statements.
a. m∠1 + m∠2 = m∠3 + m∠4
Here m∠1 and m∠2 are supplementary angles add upto 180 degrees.
m∠3 and m∠4 are supplementary angles add upto 180 degrees.
Therefore, the statement is true.
b. m∠1 + m∠5 = m∠3 + m∠4
m∠1 + m∠5 = 180 same side of the adjacent angles.
m∠3 + m∠4 = 180, supplementary angles add upto 180 degrees.
Therefore, the statement is true.
Now let's check c.
m∠1 + m∠6 = m∠4 + m∠6
We can cancel out m∠6, we get
m∠1 = m∠4 which is not true
Now let's check d.
m∠3 + m∠4 = m∠7 + m∠4
We can cancel out m∠4, we get
m∠3 = m∠7, alternative interior angles are equal.
It is true.
Therefore, answer is c. m∠1 + m∠6 = m∠4 + m∠6
Answer:A=x(x-4)-0.5(6)(x-4)-2(7)
Step-by-step explanation:
A=x(x-4)-(0.5(6)(x-4) + 2(7))
A=x(x-4)-0.5(6)(x-4)-2(7)