Answer:
P(t)=30
Step-by-step explanation:
Plug in t=6 into the equation: P(t)=t^2-t
So P(t)= (6)^2-6
P(t)=36-6
P(t)=30
Answer:
D: {-20, -13, 1, 6}
R: {-20, -8, 11, 13}
Step-by-step explanation:
Given the relation, {(–20, 11), (6, –8), (1, –20), (–13, 13)}, all x-values (inputs) make up the domain of the relation while all y-values make up the range of the relation.
Therefore:
Domain: {-20, -13, 1, 6}
Range: {-20, -8, 11, 13}
So, let's look at the problem once again.
8%, or 8/100 of the bag were green jelly beans.
Let's see what we can do to find out a number of other jelly beans, not including the green ones.
We know that 92% of jelly-beans are not green.
92% is 11.5 times more than 8%
(92/8)
24 (or 8%) times 11.5 = 276
276 - number of jelly beans that are not green.
276 plus 24 = 300.
Answer: 300 jelly beans were in one bag.
Answer:
k= 15 every two months
Step-by-step explanation: so you started with 3 and you gained fifth teen in two months so every two months you will gain fifth teen mice.