I think that gain of Silva, in July, is:
<span>60+<span>110100</span>∗60=60+<span>1110</span>∗60=60+66=126$</span><span>
so A.</span>
Since the sample is greater than 10, we can approximate this binomial problem with a normal distribution.
First, calculate the z-score:
z = (x - μ) / σ = (37000 - 36000) / 7000 = 0.143
The probability P(x > 37000$) = 1 - P(<span>x < 37000$),
therefore we need to look up at a normal distribution table in order to find
P(z < 0.143) = 0.55567
And
</span>P(x > 37000$) = 1 - <span>0.55567 = 0.44433
Hence, there is a 44.4% probability that </span><span>the sample mean is greater than $37,000.</span>
Um -1/3(24+3)-1 = -10
So -10 is the answer
Answer:
0.41 cm
Step-by-step explanation:
The scale on the map is 1 in 86 mi.
This means that, 1 cm on the map represents 86 miles in real life, or on earth.
Then we're told that in real life, a distance is 35 miles, and how far they are on the map.
If 1 cm equals 86 miles, then we can say that x cm equals 35 miles
1 cm ----> 86
x cm ----> 35
x * 86 = 35 * 1
x = 35 / 86
x = 0.41 cm
Therefore, they must be 0.41 cm farther or closer apart on the map scale.
