Q+B=13. When B+3=0
You have 2 separate equations.
First solve the 2nd equation for B:
B +3 = 0
Subtract 3 from both sides:
B +3 - 3 = 0-3
Simplify:
B = -3
Now we have a value for B, we can replace b with -3 in the first equation and solve for Q:
Q + -3 = 13
Add 3 to each side:
Q + -3 + 3 = 13+3
Simplify:
Q = 16
So you have Q = 16 and B = -3
What first of all this is a test second how are we supposed to do that where can we find M
Answer:
I'm sorry for answering late I just saw this but
Step-by-step explanation:
1. is 34
2. is 12
3. I really dont understand that one
But try your best and multiply and division always come first before u add and subtract
Answer:
Solutions are (6,3) and (-2,3).
Step-by-step explanation:
From the first equation given we can write:
substituting for 
in the second equation given we get
∴ y=3
Putting y=3 in the first equation we get
x-2 = ±4
Hence x=6 or x=-2.
