The sum of three consecutive odd numbers is 63. What is the smallest of these numbers?
2 answers:
Answer: The smallest number = 19
Step-by-step explanation:
We'll call X the smallest of those odd numbers
Then x + (x+2) + (x+4) = 63
X + X + 2 + X + 4 = 63
3X + 6 = 63
3X = 63 - 6 = 57
X = 57/3 = 19
The three consecutives odd numbers are 19, 21, 23
The sum = 19+21+23 = 63
Your answer : The smallest number = 19
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Answer:
in. by 10 in.
Step-by-step explanation:
2 ft by 3 ft, inches is:
2 * 12 = 24 inch
3 * 12 = 36 inch
24 * 36
Thus, to make 36 into 10, we divide 36 by 3.6 to get 10:
36/3.6 = 10
To keep ratio equal, we need to divide 24 by 3.6 to get:
24/3.6 =
Thus, Third answer choice is right.
The required probability is
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that,
Probability for first draw to be non-defective
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective
(printers after first slot = 10; total defective printers = 2)
Then, total probability