The spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.
Explanation:
When a spring is stretched or compressed its length changes by an amount x from its equilibrium length then the restoring force is exerted.
spring constant is k = 1.00 * 10^3 N/m
mass is x = 20.0 cm
According to Hooke's law, To find restoring force,
F = - kx
= - 1.00 *10 ^3 * 20.0
F = 20000 N/m
Thus, the spring has a spring constant of 1.00 * 10^3 N/m and the mass has been displaced 20.0 cm then the restoring force is 20000 N/m.
<h3>A boy who is riding his bicycle, moves with an initial velocity of 5 m/s. Ten second later, he is moving at 15 m/s. What is his acceleration?</h3>
<h3>Initial Velocity (<em>u</em>) - 5 m/s</h3><h3>Final Velocity (<em>v</em>) - 15 m/s</h3><h3>Time (<em>t</em>) - 10 sec</h3>
<h3>If the velocity of an object changes from an initial value <em>u </em>to the final value <em>v </em>in time <em>t,</em><em> </em>the acceleration <em>a</em> is, </h3><h3>
</h3><h3>
</h3>
<h3>His acceleration is </h3><h3>
</h3><h3 /><h3 />
Answer:
The potential energy is 189nm
Explanation:
Answer:
The distance the piece travel in horizontally axis is
L=3.55m
Explanation:
Now the angular velocity is the blade speed so:
assuming no air friction effects affect blade piece:
time for blade piece to fall to floor
Now is the same time the piece travel horizontally
blade piece travels HORIZONTALLY = (24.5)(0.397) = 9.73 m ANS