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2 years ago

12

What are the ecological consequences of acidification of rain and oceans?

1 answer:

LUCKY_DIMON [66]2 years ago

4 0

Answer:

Some effects include:

Alumminum particles reach aquatic environments and can harm fish and other wildlife. In these ecosystems acidity can also prevent fish eggs from hatching.
Acid rain can remove important minerals and nutrients from the soil preventing trees to grow, it can also poison them due to the aluminum particles.
The fenomenon of e pisodic acidification can occur, this means that acidity can be present in m elting snow generating small lapses of higher acidity
It can occur a n itrogen pollution

I hope you find this information useful and interesting! Good luck!

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Tyrone, an 85-kg teenager, runs off the end of a horizontal pier and lands on a free-floating 130-kg raft that was initially at

Ghella [55]

Answer:u=4.04 m/s

Explanation:

Given

Mass m=85 kg

mass of Raft M=130 kg

velocity of raft and man v=1.6 m/s

Let initial speed of Tyrone is u

Conserving Momentum as there is no external Force

$mu=(M+m)v$

$85\times u=(85+130)\cdot 1.6$

$u=\frac{215}{85}\cdot 1.6$

$u=2.529\cdot 1.6=4.04 m/s$

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2 years ago

A rocket burns fuel as it shoots into the sky. What happens to the mass and volume of the rocket?

diamong [38]

Answer:

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2 years ago

How does an inclined plane change distance and how does it change direction

ElenaW [278]

Objects are known to go down because of a unbalanced force

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2 years ago

An object of mass kg is released from rest m above the ground and allowed to fall under the influence of gravity. Assuming the f

IgorLugansk [536]

Answer:

Explanation:

From, the given information: we are not given any value for the mass, the proportionality constant and the distance

Assuming that:

the mass = 5 kg and the proportionality constant = 50 kg

the distance of the mass above the ground x(t) = 1000 m

Let's recall that:

$v(t) = \dfrac{mg}{b}+ (v_o - \dfrac{mg}{b})^e^{-bt/m}$

Similarly, The equation of mption:

$x(t) = \dfrac{mg}{b}t+\dfrac{m}{b} (v_o - \dfrac{mg}{b}) (1-e^{-bt/m})$

replacing our assumed values:

where $v_=0 \ and \ g= 9.81$

$x(t) = \dfrac{5 \times 9.81}{50}t+\dfrac{5}{50} (0 - \dfrac{(5)(9.81)}{50}) (1-e^{-(50)t/5})$

$x(t) = 0.981t+0.1 (0 - 0.981) (1-e^{-(10)t}) \ m$

$\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}$

So, when the object hits the ground when x(t) = 1000

Then from above derived equation:

$\mathbf{x(t) = 0.981t-0.981(1-e^{-(10)t}) \ m}$

$1000= 0.981t-0.981(1-e^{-(10)t}) \ m$

By diregarding $e^{-(10)t} \ m$

$1000= 0.981t-0.981$

1000 + 0.981 = 0.981 t

1000.981 = 0.981 t

t = 1000.981/0.981

t = 1020.36 sec

7 0

2 years ago

HELP⚠️⚠️

alexgriva [62]

Answer:

I think u are traeling at speed of light and not ur friend

Explanation:

4 0

2 years ago

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