Sqrt(1-3x)=x+3
[sqrt(1-3x)]^2=(x+3)^2
1-3x=(x+3)(x+3)
1-3x=x^2+6x+9
-3x=x^2+6x+8
0=x^2+9x+8
The answers are -1 and -8 BUT, we have to plug them back into the original equation to make sure we don't get a negative under the square root sign.
After doing this, we realize that only -1 works, so the answer is x=-1
Sorry that this took forever to answer. I was thinking of a good way to explain this, and if you need any further explanation, message me:)
Best wishes:)
Answer:
6x * 1/2 - 3 (* means multiplying)
Step-by-step explanation:
In this problem, you are using communitive property and so you are just changing the problem to an equal situation.
if you're trying to solve for x, and it is equal to zero, then it would be -3. plug it in and it would all cancel out
Answer:
Step-by-step explanation:
Since you are doing squared, you have to multiply the exponents.
4 * 2 = 8
Answer:
c
Step-by-step explanation:
its c because i got 100% on the topic test