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2 years ago

Solving systems of equations by elimination.

Mathematics

1 answer:

Tamiku [17]2 years ago

5 0

For the first one, x=-1, y=-8

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What is the area of the trapezoid with height 13 units?

Rina8888 [55]

A = 1/2(15+7+15+7)(13)
A= 1/2(44)(13)
A = 286

answer
286

6 0

2 years ago

Read 2 more answers

If (angle)A and (angle)B are supplementary, and m(angle)A = 57°, what is m(angle)B?

Sedbober [7]

Answer:

123°

Step-by-step explanation:

Supplementary angles add up to be 180 degrees.

This means angles A and B will add up to be 180 degrees.

We can find the measure of angle B by subtracting 57 from 180

180 - 57

= 123

So, the measure of angle B is 123 degrees

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2 years ago

if x/b-c=y/c-a=z/a-b, prove that x+y+x=0.please help me ... this is my homework. I will follow you plz . anyone.

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Answer:

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2 years ago

You order from a catalog the following office supplies: 10 boxes of paper, each box is 6 pounds and 36 boxes of pens, each box w

babymother [125]

$40.50 10 boxes at 6lbs = 60lbs

36 boxes at 12 ounces = 432 ounces dived by 16(16 oz in a lbs)= 27 lbs

60 lbs plus 27 lbs = 87 lbs total weight

87lbs - 20lbs($12)= 67lbs - 30 lbs($10)= 37lbs x .50($.50 per pound)= $18.50

$12+$10+$18.50= $40.50

6 0

2 years ago

Select all the expressions that are equivalent to (2)^n+³

eimsori [14]

Answer:

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

$a^{m}$ × $a^{m}$ = $a^{m+n}$
$(a^{m})^{n}$ = $a^{m*n}$

Now let us find the equivalent expressions of $(2)^{n+3}$

∵ 4 = 2 × 2

∴ 4 = $2^{2}$

∴ $(4)^{n+2}$ = $(2^{2})^{n+2}$

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴ $(4)^{n+2}$ = $(2)^{2n+4}$

∵ 4 = 2 × 2

∴ 4 = 2²

∴ $4(2)^{n+1}$ = 2² × $(2)^{n+1}$

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴ $4(2)^{n+1}$ = $(2)^{n+3}$

∵ 8 = 2 × 2 × 2

∴ 8 = 2³

∴ $8(2)^{n}$ = 2³ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴ $8(2)^{n}$ = $(2)^{n+3}$

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = $2^{4}$

∴ $16(2)^{n}$ = $2^{4}$ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴ $16(2)^{n}$ = $(2)^{n+4}$

$(2)^{2n+3}$ is in its simplest form

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

3 0

2 years ago