Answer:
A on edge
Step-by-step explanation:
<span>The </span>area<span> of the </span>sector<span> of a </span>circle<span> with a </span>radius<span> of </span>8 centimeters<span> is </span>125.6 square centimeters<span>. The </span>estimated value<span> of is </span>3.14<span>. ... First find the </span>area<span> of the entire </span>circleA=3.14*82<span>=200.96 </span>cm2<span> this is the </span>area<span> for 360</span>o<span> or entire </span>circle<span>. The </span>area<span> of the </span>sector<span> represents an</span>angle<span> less then 360 and is simply the ratio of ...</span>
Answer:
Evaluate each expression for a = 4, b = 2, and c = 5.
c − a
5x+4=114
5x= 110
X=22
114+ 3(22)-24=156
180-156=24
2y=24
Y=12
Answer:
ASA
ΔFGH ≅ ΔIHG ⇒ answer B
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets prove the two triangles FGH and IHG are congruent by on of
the cases above
∵ FG // HI and GH is transversal
∴ m∠FGH = m∠IHG ⇒ alternate angles
- In the two triangles FGH and IHG
∵ m∠FHG = m∠IGH ⇒ given
∵ m∠FGH = m∠IHG ⇒ proved
∵ GH = HG ⇒ common side
∴ ΔFGH ≅ ΔIHG ⇒ ASA
* ASA
ΔFGH ≅ ΔIHG
