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2 years ago

What's the quotient of I? 5+5i divided by 2+I

1 answer:

7 0

$if\ "i"\ is\ the\ imaginary\ unit:\sqrt{-1}=i\Rightarrow i^2=-1\\\\then\\\\\frac{5+5i}{2+i}=\frac{5+5i}{2+i}\cdot\frac{2-i}{2-i}=\frac{10-5i+10i+5i^2}{2^2-i^2}=\frac{10+5i-5}{4+1}=\frac{5+5i}{5}=\boxed{1+i}$

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You earn $8.50 per hour at your summer job right and solve any quality any quality that represents the number of hours you need

irina1246 [14]

He should work for 24 hours.

7 0

2 years ago

Please help me out!!!!!

Neko [114]

Given:

The zeros of the polynomial are $-2,\pm 5,4$ .

Degree = 4

Leading coefficient = 1

To find:

The polynomial.

Solution:

If c is a zero of a polynomial, then (x-c) must be a factor of the polynomial.

Here, -2,4,-5, 5, are zeros of the required polynomial, so (x+2), (x-4), (x+5), (x-5) are factors of required polynomial.

$p(x)=(x+2)(x-4)(x+5)(x-5)$

$p(x)=(x^2-4x+2x-8)(x^2-5^2)$ $[\because a^2-b^2=(a-b)(a+b)]$

$p(x)=(x^2-2x-8)(x^2-25)$

Using distributive property, we get

$p(x)=x^2(x^2-25)-2x(x^2-25)-8(x^2-25)$

$p(x)=x^4-25x^2-2x^3+50x-8x^2+200$

On combining like terms, we get

$p(x)=x^4-2x^3+(-25x^2-8x^2)+50x+200$

$p(x)=x^4-2x^3-33x^2+50x+200$

Here, the leading coefficient is 1. So, it is the required polynomial.

Therefore, the correct option is E.

3 0

2 years ago

ILL MARK BRAINLIEST!!! PLEASE HELP!

eduard

Answer:

The quadratic equation is X^2 -26X +144=0

Step-by-step explanation:

You can do it shortly by using the formula

X^2-(sum)x+ product

which will give you

X^2- (8+18)x+8×18

=X^2 -26x +144

=X^2 -8x-18x + 144

=(X^2-8x)(-18x+144)

=X(X-8)-18(x-8)=0

(X-18)(X-8)=0

X-18=0 And X-8=0

X=18 X=8

. Therefore the quadratic equation is X^2 -26X +144

3 0

2 years ago

Determine whether a figure with the given vertices is a parallelogram. Use the method indicated.

aliya0001 [1]

Answer with explanation:

The coordinates of four points of Quadrilateral ABCD are

A(4, 5), B(–7, –10), C(–4, –9), D(7, 6)

$AB=\sqrt{(4+7)^2+(5+10)^2}\\\\AB=\sqrt{121+225}\\\\AB=\sqrt{346}\\\\BC=\sqrt{(-7+4)^2+(-10+9)^2}\\\\BC=\sqrt{9+1}\\\\BC=\sqrt{10}\\\\CD=\sqrt{(4+7)^2+(5+10)^2}\\\\CD=\sqrt{121+225}\\\\CD=\sqrt{346}\\\\DA=\sqrt{(7-4)^2+(6-5)^2}\\\\DA=\sqrt{9+1}\\\\DA=\sqrt{10}$

Slope between two points is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m_{1}=\frac{-10-5}{-7-4}\\\\=\frac{-15}{-11}\\\\m_{1}=\frac{15}{11}\\\\m_{2}=\frac{-9+10}{-4+7}\\\\m_{2}=\frac{1}{3}\\\\m_{3}=\frac{6+9}{7+4}\\\\m_{3}=\frac{15}{11}\\\\m_{4}=\frac{6-5}{7-4}\\\\m_{4}=\frac{1}{3}$

As slope of opposite sides are equal and length of Opposite sides are equal.So,the given Quadrilateral is a Parallelogram.

Option A

Yes; The opposite sides are congruent and have the same slope.

6 0

2 years ago

128 is 74% of what number if necessary round your answer to the nearest hundredth

topjm [15]

74% * x = 128
x=128/74%
x=172.97 (nearest hundredth)

4 0

2 years ago

Read 2 more answers