The number of tests that it would take for the probability of committing at least one type I error to be at least 0.7 is 118 .
In the question ,
it is given that ,
the probability of committing at least , type I error is = 0.7
we have to find the number of tests ,
let the number of test be n ,
the above mentioned situation can be written as
1 - P(no type I error is committed) ≥ P(at least type I error is committed)
which is written as ,
1 - (1 - 0.01)ⁿ ≥ 0.7
-(0.99)ⁿ ≥ 0.7 - 1
(0.99)ⁿ ≤ 0.3
On further simplification ,
we get ,
n ≈ 118 .
Therefore , the number of tests are 118 .
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1)
x+10<-7
bring 10 to the other side
x<-10-7
x<-17
2)
-3x-4>5
bring -4 to the other side
-3x>9
divide -3 at the other side, since it is negative it changes to less than
x<-3
First of all, you must change 40% into a decimal by multiplying by 100⇒.40
Then you divide 55 by .40
55÷.40=137.5
Therefore, 55 is 40% of 137.5
Answer:
No
Step-by-step explanation:
30% is the same as 3/10
3/7 is about the same as 43%
There is a difference among the percentage so no it's not correct
