2 years ago

Can you solve this????? Super hard!

1 answer:

6 0

Answer:

$\textbf{J. }\dfrac{1}{x^2-x}$

Step-by-step explanation:

Factor the denominator and cancel the common factor.

$\dfrac{x+1}{x^3-x}=\dfrac{x+1}{x(x^2-1)}=\dfrac{x+1}{x(x-1)(x+1)}=\dfrac{1}{x(x-1)}\\\\=\boxed{\dfrac{1}{x^2-x}}$

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1700, just use the inverse operation. The problem would look like this ( not inverse operation ) x ÷ 33 1/3 = 51

All you have to do is multiply the two numbers.

51 x 33 1/3 = 1700

Now plug it back in and check

1700 ÷ 33 1/3 does indeed equal 51.

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