<u>Answer:</u>
<h3>
<u>Step-by-step explanation:</u></h3>
According to Question , a plane travels 120 miles in 2 hours. So here we will use unitary method .
<h3>
<u>Hence</u><u> </u><u>it </u><u>will</u><u> </u><u>cover</u><u> </u><u>30</u><u>0</u><u> </u><u>miles</u><u> </u><u>in</u><u> </u><u>5</u><u> </u><u>hours</u><u> </u><u>.</u></h3>
Here it was a case of direct proportion in which if two things are directly proportional to each other. If one thing thing increases then the value of second also increases. Here if the time increases then the distance also increases
0.89 x 0.98 = 0.8722, so you answer is 0.8722
G=greeting cards
Equation A- 32+.33(g)
Equation B- T= 32+.33(10)
The answer: T=$35.30
Answer:
(A) -3 ≤ x ≤ 1
Step-by-step explanation:
The given function is presented as follows;
h(x) = x² - 1
From the given function, the coefficient of the quadratic term is positive, and therefore, the function is U shaped and has a minimum value, with the slope on the interval to the left of <em>h</em> having a negative rate of change;
The minimum value of h(x) is found as follows;
At the minimum of h(x), h'(x) = d(h(x)/dx = d(x² - 1)/dx = 2·x = 0
∴ x = 0/2 = 0 at the minimum
Therefore, the function is symmetrical about the point where x = 0
The average rate of change over an interval is given by the change in 'y' and x-values over the end-point in the interval, which is the slope of a straight line drawn between the points
The average rate of change will be negative where the y-value of the left boundary of the interval is higher than the y-value of the right boundary of the interval, such that the line formed by joining the endpoints of the interval slope downwards from left to right
The distance from the x-value of left boundary of the interval that would have a negative slope from x = 0 will be more than the distance of the x-value of the right boundary of the interval
Therefore, the interval over which <em>h</em> has a negative rate of change is -3 ≤ x ≤ 1