Answer:(6, -1)
Step-by-step explanation:
To ease your problem, consider "L" as you x-axis
Then the coordinate become:
A(- 4 , 3) and B(1 , 2) [you notice that just the y's changed]
This is a reflection problem.
Reflect point B across the river line "L" to get B', symmetric of B about L.
The coordinates of B'(1 , -1) [remember L is our new x-axis]
JOIN A to B' . AB' intersect L, say in H
We have to find the shortest way such that AH + HB = shortest.
But HB = HB' (symmetry about L) , then I can write instead of
AH + HB →→ AH + HB'. This is the shortest since the shortest distance between 2 points is the straight line and H is the point requiered
Answer:
2.0 seconds
Step-by-step explanation:
<u>Given quadratic functions</u>:
To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:
<u>Factor</u> the quadratic:
Apply the <u>zero-product property</u> to solve for x:
Therefore, the balloons collided at 1 second and 2 seconds.
To find at which time the highest point of collision occured, substitute both values of x into one of the functions:
Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.
Learn more about quadratic systems of equations here:
brainly.com/question/27930827
Answer:9/4
Step-by-step explanation:
99/8*2/11=9/4*1/1=9/4
You can cancel out 99 and 11 to 9 and 1 as they are multiples of eac hother and you can do the same for 8 and 2 to 4 and 1
An illusionist needs up to 10 volunteers for a show. the illusionist needs no fewer than 4 female volunteers. let x represent the number of femalevolunteers and y represent the number of male volunteers.which inequalities model the situation?select each correct answer.
A- x + y < 10
<span>B- x + y ≤ 10 & </span>x ≥ 4
C- x > 4
D- x ≥ 4
E- y > 0
G- y ≥ 0
Solution :
option "B" is correct. Because the total number of male and female should be upto 10. and the number of female should be equal or greater than 4 but not less than it.