Answer:
Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).
Step-by-step explanation:
Misha's group was asked to write an expression equivalent to
7y²z + 3yz² - 3
When Mr. Chen checked their answers, he found only one to be correct.
And she was Helena.
Helena gave the answer as (7y²z + 6yz²- 5 - 3yz² + 2) which is equivalent to (7y²z + 3yz² - 3).
Because, (7y²z + 6yz²- 5 - 3yz² + 2)
= 7y²z + (6yz² - 3yz²) - (5 - 2)
= 7y²z + 3yz² - 3 (Answer)
Answer:
TRUE
Step-by-step explanation:
A quadratic equation can be found that will go through any three distinct points that ...
- satisfy the requirements for a function
- are not on the same line
_____
The key word here is "may." You will not be able to find a quadratic intersecting the three points if they do not meet both requirements above.
15 is the awnser too this one
So since they are similar
AC/BC=CD/CE
so
(66-x)/30=(x+4)/5
times both sides by 5
(66-x)/6=x+4
times both sides by 6
66-x=6(x+4)
distribute
66-x=6x+24
add x to both sides
66=7x+24
minus 24 from both sides
42=7x
divide both sides by 7
6=x
x=6 units
