the answer is in the picture above
Answer:
2116
Step-by-step explanation:
hope this helps :)
Answer:
Step-by-step explanation:
Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?
Let p(x)=kpx+dp and q(x)=kqx+dq than
f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7
p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7
(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)
So you want:
−2kpk2q=0
and
kpkq=−1
and
2kpd2p−3kpdq+7=0
Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .
Answer: there are no such linear functions.
F = kry
f/kr = y
y = f/kr
Answer: y = f/kr
*Hope that helps and enjoy Brainly:)
Answer:
2/5 or 40%
Step-by-step explanation:
.40 is 40 hundredths or 40/100
40/100 can be reduced to 20/50 and reduced again to 10/25 and one more time to 2/5
Percentages are fractions out of 100 so 40/100 would be 40%.