Answer:
Step-by-step explanation:
Circumference C=2πr r=radius
C=2(3.14)9.7
C=60.9
from what I know
A=4
B=3
C=2
and a plus adds 0.33 and a minus minuses 0.33
question wants us to find yearly average or average per 1 year
since these grades span over 2 years, we must divide the total average by 2
averagefresh=sum of fresh grades/4 grades per year
averagesoph=sum of soph grades/4 grades per year
yearlyaverage=(averagefresh+averagesoph)/2
freshman:
(C)+(B)+(A)+(C-)=2+3+4+(2-0.33)=10.67
sophomore:
(B+)+(A-)+(C+)+(B-)=(3+0.33)+(4-0.33)+(2+0.33)+(3-0.33)=12
averagefresh=10.67/4=2.6675
averagesoph=12/4=3
yearlyaverage=(2.6675+3)/2=2.83375
so it's about a average
The coordinates of B would be (2, -4)
In order to find this, we need to know that the value of M's points will always be the average of A and B's points. This is because it is the midpoint. Therefore we can use the following formula.
Value of x
(A + B)/2 = M
(-8 + B)/2 = -3
-8 + B = -6
B = 2
Then we can do the same for the y values
Value of y
(A + B)/2 = M
(-2 + B)/2 = -3
-2 + B = -6
B = 4
Answer:
-4.42
Step-by-step explanation:
Given the following :
Population mean (pm) = 8 hours
Sample mean (sm) = 6.9 hours
Number of observations (n) = 101 students
Sample standard deviation (sd) = 2.5
Using the t-statistic formula :
[(sm - pm) / (sd/√n)]
Hence,
[(6.9 - 8) / (2.5/√101)]
[(-1.1) / (2.5/10.05)]
-1.1 / 0.2487562
= −4.422
The test statistic = - 4.42 to the nearest hundredth.