As x approaches 3 from the right, the limit is 3. There is a closed hole up there AT x=3 y=7, but we don't care about what happens AT x=3, only what happens as x APPROACHES 3.
Answer:
<u>The answer is option C. 6a-7</u>
Step-by-step explanation:
Given that
5(3a-1)-2(3a-2)=3(a+2)+v
Solve for v
∴ v = 5(3a-1)-2(3a-2) - 3(a+2)
∴ v = 15a - 5 - 6a + 4 - 3a - 6
∴ v = 15a - 6a - 3a - 5 + 4 - 6
∴ v = 6a - 7
<u>So the answer is option C. 6a-7</u>
Answer: See below
Step-by-step explanation:
Make a table with first set of numbers as 1,3. Multiply both the numbers of this set sequentially by natural numbers to get the following table
1 2 3 4 5 6 7 8 9 10......
3 6 9 12 15 18 21 24 27 30......
We see that in each set of numbers the 2nd number is 3 times the first number.
If we plot these sets of numbers on a graph paper, we get a model depicting all the points which satisfy this ration requirement.
Answer:
62
Step-by-step explanation:
(-8)^2-2
64-2 = 62
