Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:
Re-write 'em as a standard form:
So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:
And they do not have any collision point
Answer:
99+3b
Step-by-step explanation:
The original equation would be 3(33+b), but simplifying it would get 99+3b.
Answer:
<u>The system has two solutions:</u>
<u>x₁ = 5 ⇒ y₁ = -10</u>
<u>x₂ = -2 ⇒ y₂ = 11</u>
Step-by-step explanation:
Let's solve the system of equations, this way:
y = -3x + 5
y = x ² - 6x - 5
Replacing y in the 2nd equation:
y = x ² - 6x - 5
-3x + 5 = x ² - 6x - 5
x ² - 3x - 10 = 0
Solving for x, using the quadratic formula:
(3 +/- √(9 -4 * 1 * -10))/2 * 1
(3 +/- √9 + 40)/2
(3 +/- √49)/2
(3 +/- 7)/2
x₁ = 10/2 = 5
x₂ = -4/2 = -2
x₁ = 5 ⇒ y₁ = -10
x₂ = -2 ⇒ y₂ = 11
<u>As we can see the system has two different solutions</u>
Answer:
the answer is d
Step-by-step explanation:
i just know its fine.
Answer:
5/1 = 5
Step-by-step explanation:
because 5/1 equals 5.
