What do you mean
what are you trying to figueout?
Answer:
Step-by-step explanation:
1
3
3(x² + 1)
2
6
6(3y² - 1)
3
m²
m²(n² + 3)
4
6
6(x³ + 6)
5
6
6(x³ + 3x² + 4)
6
5
5(a³ + 5a² - 7a + 4)
7
8
8(2m³ + 3m² + 2)
8
5
5(5x²y + 3xy² + 6)
9
16x
16x(2x^4 + 4x³ + 1)
10
7xy
7xy(3x²y - x + 6)
11
-a^4
-a^4(3a² + 4a + 1)
12
4xy
4xy(x - 4xy + 5y)
13
6y
6y(-4x² + x²y + 5y)
14
2
2(9a² - 18a²b² + 22b²)
15
-3xy
-3xy(5x²y + 15xy + 11y)
16
4ab
4ab(ab^6 - 8ab^5 + 4b)
17
17xy
17xy(x - 2)
18
n
n(3m² - 39m²n - 13n)
19
5t
5t(-8t + ts + 20s²)
20
p
p(6p³q + qr - 3r)
Answer:
I have absolutely no clue sorry buddy
Step-by-step explanation:
There is no step-by-step explanation
What does the and 2 mean? Does it mean times two or plus two?
Step-by-step explanation:
Answer:
Two complex (imaginary) solutions.
Step-by-step explanation:
To determine the number/type of solutions for a quadratic, we can evaluate its discriminant.
The discriminant formula for a quadratic in standard form is:
We have:
Hence, a=3; b=7; and c=5.
Substitute the values into our formula and evaluate. Therefore:
Hence, the result is a negative value.
If:
- The discriminant is negative, there are two, complex (imaginary) roots.
- The discriminant is 0, there is exactly one real root.
- The discriminant is positive, there are two, real roots.
Since our discriminant is negative, this means that for our equation, there exists two complex (imaginary) solutions.