4) the ice has to be heated up to above 0c first, as it is continuing to cool the water back toward 0c
5) 0.0338 kcal
(33.8/1000)
6) 1.2506 kcal
((33.8*37.0)/1000)
Yes, refer to the previous answer.
Covalent Bond Name :N6Cl10
Explanation:
- Covalent compounds are named by using numerical prefixes to identify the number of atoms in the molecule. For example Carbon Dioxide CO2 and Carbon Monoxide CO . ... Drop the double vowel for the prefix and the element of the second element in the compound.
- The three types as mentioned in the other answers are polar covalent, nonpolar covalent, and coordinate covalent. The first, polar covalent, is formed between two nonmetals that have a difference in electronegativity. They share their electron density unevenly.
- Examples of Covalent Bond: Water. An example is water. Water consists of a covalent bond containing hydrogen and oxygen bonding together to make H2O. ...Diamonds. A diamond is an example of Giant Covalent bond of carbon. A diamond has a giant molecular structure. ...Vulcanized rubber. Another example is vulcanized rubber.
- Covalent bonds are especially important since most carbon molecules interact primarily through covalent bonding. Covalent bonding allows molecules to share electrons with other molecules, creating long chains of compounds and allowing more complexity in life.
Answer:
2Zn + 2HCI ➡️ ZnCI2 + H2
LHS of equation
Z = 2
H = 2
Cl = 2
RHS of equation
Zn = 1
Cl =2
H =2
as Zn is not equal in number of atoms on both sides of the equation, the equation does not obey the law of conservation of mass
Explanation:
the law of conservation mass states that the mass of an isolated system cannot be created nor destroyed by any chemical reaction or physical transformation. thus, there must be an equal number of atoms of an element present on both sides of the equation.
Answer:
The answer to your question is Q = 18702.5 J
Explanation:
Data
mass of water = m = 447 g
Cp = 4.184 J/g°C
Temperature 1 = T1 = 25°C
Temperature 2 = T2 = 35°C
Heat = Q = ? Joules
Process
1.- Write the formula to calculate heat
Q = mCp(T2 - T1)
2.- Substitution
Q = (447)(4.184)(35 - 25)
3.- Simplification
Q = (447)(4.184)(10)
4.- Result
Q = 18702.5 J
