Solve and graph each Inequality.<br><br> l2c-5l<9

What is the internal angle sum of a quadrilateral? (Hint: A quadirlateral has 4 sides.) OA) 90 OB) 180 OC) 360 OD 540

shtirl [24]

The internal angle sum of a quadrilateral is :

C. 360°

The sum of internal angles of a polygon is determined by a formula :

$\longmapsto (n - 2) × 180°$

where n represents number of sides.

In a quadrilateral there are four sides,

So, plugging 4 in the formula :

$(4 - 2) \times 180°$

$2 \times 180°$

$360°$

_____________________________

$\mathrm{ \#TeeNForeveR}$

5 0

2 years ago

Read 2 more answers

when derek planted a tree it was 36 inches tall. the tree grew 1 1/4 inches per year the tree is now 44 3/4 inches tall. how man

Vikentia [17]

7 1/2 years ago to be precise

If correct brainley please

Thank you

5 0

2 years ago

Why do you subtract the area of the circle from the total

posledela

Answer:

To find the area of a circle with the radius, square the radius, or multiply it by itself. Then, multiply the squared radius by pi, or 3.14, to get the area. To find the area with the diameter, simply divide the diameter by 2, plug it into the radius formula, and solve as before.

Step-by-step explanation:

5 0

2 years ago

1 A puppy named Fuzzy started out at 3 pounds and gained 1/4 pounds every month. The

ANEK [815]

Answer:

It would be D, 1/4.

Step-by-step explanation:

I hope this helps you!

6 0

2 years ago

Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

7 0

2 years ago

Solve and graph each Inequality. l2c-5l<9