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Anuta_ua [19.1K]

2 years ago

10

A recipe calls for 1/2 teaspoon of crushed red pepper and 3/4 teaspoon of thyme leaves. What is the unit rate of teaspoons of cr

ushed pepper to 1 teaspoon of thyme leaves?

1 answer:

Tems11 [23]2 years ago

4 0

2:4
1:2
Hope this helps!!

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Which quadratic rule represents the data in the table?

NeX [460]

Since there are already choices in the question, I suggest you just substitute in the values of x to each choice and check whether the corresponding value for y appears. This is also called the trial and error method in multiple choice.

The answer that represents the data in the table is C. <span>y = x^2 – 5.</span>

3 0

2 years ago

Lorena received a $50 gift card to an online store she wants to purchase some bracelets that cost $8 each there will be a $10 ov

Setler79 [48]

Minus the 10 from the 50, which makes 40. then divide 40 by 8
50-10=40
40÷8=5
n=5

3 0

2 years ago

Find the area of the kite !!!! PLEASE HELP!!!!

Andrew [12]

ANSWER

D. 18 m^2

EXPLANATION

The area of a kite is half the product of the diagonals.

The diagonals of the kite are

3+3=6m

and

2+4=6m

The area of the kite

$= \frac{1}{2} \times 6 \times 6$

$= 3 \times 6$

$= 18 {m}^{2}$

The correct answer is D.

7 0

2 years ago

in a company 75% of the workers are women. of 850 people work for the company who aren't women, how many workers are there in al

Nadya [2.5K]

There’s one method
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4 0

1 year ago

A cup of coffee with temperature 155degreesF is placed in a freezer with temperature 0degreesF. After 5 minutes, the temperatur

Leviafan [203]

Answer:

45.50° F

Step-by-step explanation:

As per Newton's law,

$T(t) = T_{s}+(T_{0} + T_{s})e^{-kt}$

When T(t) is the final temperature

$T_{s}$ = Temperature of surrounding

$T_{0}$ = Initial temperature

t =duration of cooling

k = constant

$103=0+(155-0)e^{-k\times 5}$

$103=155e^{-5k}$

Now take natural log on both the sides

$ln(103)=ln(155e^{-5k})$

$ln(103)=ln(155)+ln(e^{-5k})$

$ln(103)=ln(155)=-5k$

4.6347 - 5.0434 = -5k

$k=\frac{0.40872}{5}$

k = 0.0817

$T(t)=0+(155-0)e^{(0.0817\times 15)}$

= $155e^{-1.226}$

= 155 (02935)

= 45.49 ≈ 45.50° F

8 0

3 years ago