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2 years ago

4y= -6x +8 find the y-intercept

Mathematics

1 answer:

ivanzaharov [21]2 years ago

7 0

First, divide each side by 4 to get y alone on the left side.

y=-6/4x+2

The y intercept is 2

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Joey has a full 40 coins consisting of only quarters and nickels if the total value is $5.00 how many of each does joey have.

Archy [21]

Q + n = 40....q = 40 - n
0.25q + 0.05n = 5

0.25(40 - n) + 0.05n = 5
10 - 0.25n + 0.05n = 5
-0.25n + 0.05n = 5 - 10
- 0.20n = -5
n = -5 / -0.20
n = 25 <=== 25 nickels

q + n = 40
q + 25 = 40
q = 40 - 25
q = 15 <== 15 quarters

7 0

2 years ago

Read 2 more answers

There are 15 female students in Ms. Stell's World History Class. The ratio of females to males is 5:4. How many males are in her

adoni [48]

Answer:

Step-by-step explanation:

Since 15 is 3 times the ratio you multiply 4 by 3

3 0

2 years ago

Read 2 more answers

* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both

Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective $n^{th}$ terms as following:

Sequence A. $3n - 2$

Sequence B. $10 - 2n$

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the $n^{th}$ terms of the respective sequences as equal and let us verify that.

$3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}$

When we talk about $n^{th}$ terms, $n$ here is a whole number not a fractional number.

But as per the statement as stated by Sally $n$ is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0

1 year ago

Choose the best estimate for the multiplication problem below. 74 X 61

xenn [34]

C. 4200

its the number closest to 74 X 61

3 0

2 years ago

How do you do this question?

Step2247 [10]

Answer:

Step-by-step explanation:

$f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D$

7 0

2 years ago