The words that fill in the blanks in order are;
- atoms
- Electrons
- shells
- Valence electrons
- Electron distribution
- Molecules
- Basic atoms
- Charge distribution
- Interact with other molecules electron
- Harm living organisms
Atoms are composed of electrons. These electrons are arranged in shells. The number of valence electrons (outermost shell electrons) determine the kind of bonds that can be formed in a molecule.
In a molecule, charges are distributed in a unique way and the charge distribution in a molecule determines how the molecule interacts with other molecules. Different molecules can be made by arranging the same basic atoms in different ways.
Harmful substances can be formed when atoms of elements combine in new ways in the environment.
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Answer:
a) The genes present on separate chromosomes exhibit indepedent assortment.
b) The genotype of tall and purple flower parent= TTPp
The genotype of short and purple flower parent: ttPp
Explanation:
a) In a dihybrid cross, if the genes are present on the same chromosome, they will not exhibit independent assortment. The genes present on the same chromosome are called linked genes. Linked genes are inherited together. The absence of independent assortment of a linked gene gives more of parental types in F2 progeny. Therefore, if genes are not present on a separate chromosome, Mendel’s ratios deviate.
b) Alleles for tallness and purple flower are dominant. In the progeny, all the plants are tall. This means that the dominant tall plant is homozygous. With respect to flower color, the trait exhibits segregation of dominant and recessive alleles and both purple and white flower progeny are obtained. This makes both the plants heterozygous for the flower color gene.
The genotype of tall and purple flower parent= TTPp
The genotype of short and purple flower parent: ttPp
Q1. The answer is 1.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
x = 50% = 50/100 = 0.5
n = ?
(1/2)ⁿ = 0.5
log((1/2)ⁿ) = log(0.5)
n * log(1/2) = log(0.5)
n * log(0.5) = log(0.5)
n = log(0.5)/log(0.5)
n = 1
Q10. The answer is 2.
It can be calculated using the equation:
(1/2)ⁿ = x
x - decimal amount remaining,
n - a number of half-lives.
Rhyolite #2 has 25% of the parent H remaining:
x = 25% = 25/100 = 0.25
n = ?
(1/2)ⁿ = 0.25
log((1/2)ⁿ) = log(0.25)
n * log(1/2) = log(0.25)
n * log(0.5) = log(0.25)
n = log(0.25)/log(0.5)
n = -0.602 / - 0.301
n = 2
Q3. The answer is 100 million years.
A number of half-lives (n) is a quotient of total time elapsed (t) and length of half-life (H):
n = t/H
n = 1
t = ?
H = 100 000 000 years
n = t/H
t = n * H
t = 1 * 100 000 000 years
t = 100 000 000 years<span>
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