Answer:
Step-by-step explanation:
yes ,great job lxwxh
We are asked to find the probability that the student sold 11-15 T-shirts or less than 6 T-shirts.
The total number of club members = 2 + 14 + 12 + 3 + 6 + 1 = 38
Probability of 11-15 T-shirts:
From the table, 3 club members bought 11 - 15 T-shirts.
So the probability is 3/38
Probability of less than 6 T-shirts:
Less than 6 T-shirts means 1 - 5 plus 0 T-shirts.
Form the table, 14 club members bought 1 - 5 T-shirts and 2 club members bought 0 T-shirts.
Total club member who bought 1 - 5 and 0 T-shirts = 14 + 2 = 16
So the probability is 16/38
Now we have to add them together to find the probability that the student sold 11-15 T-shirts or less than 6 T-shirts.
(or means to add)
So the probability is 3/38 + 16/38 = 19/38 = 0.5000
Therefore, the correct answer is option c.
This basically says all the steps ! If you have any questions just tell me :)
Problem 1
<h3>Answer: False</h3>
---------------------------------
Explanation:
The notation (f o g)(x) means f( g(x) ). Here g(x) is the inner function.
So,
f(x) = x+1
f( g(x) ) = g(x) + 1 .... replace every x with g(x)
f( g(x) ) = 6x+1 ... plug in g(x) = 6x
(f o g)(x) = 6x+1
Now let's flip things around
g(x) = 6x
g( f(x) ) = 6*( f(x) ) .... replace every x with f(x)
g( f(x) ) = 6(x+1) .... plug in f(x) = x+1
g( f(x) ) = 6x+6
(g o f)(x) = 6x+6
This shows that (f o g)(x) = (g o f)(x) is a false equation for the given f(x) and g(x) functions.
===============================================
Problem 2
<h3>Answer: True</h3>
---------------------------------
Explanation:
Let's say that g(x) produced a number that wasn't in the domain of f(x). This would mean that f( g(x) ) would be undefined.
For example, let
f(x) = 1/(x+2)
g(x) = -2
The g(x) function will always produce the output -2 regardless of what the input x is. Feeding that -2 output into f(x) leads to 1/(x+2) = 1/(-2+2) = 1/0 which is undefined.
So it's important that the outputs of g(x) line up with the domain of f(x). Outputs of g(x) must be valid inputs of f(x).
