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WINSTONCH [101]

2 years ago

9

What is 3.125 as a improper fraction

1 answer:

Alexandra [31]2 years ago

3 0

3.125 , we can write it as

3 125/1000

3 1/8

25/8

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4x + 5y = -2 . what is the slope show ur work

lawyer [7]

4x + 5y = -2

-5 -5

4x = -5y - 2

4x/4 = -5y -2/ 4

x = -5/4 y + -1/2

4 0

2 years ago

Please help me for the love of God if i fail I have to repeat the class

Elena-2011 [213]

$\theta$ is in quadrant I, so $\cos\theta>0$ .

$x$ is in quadrant II, so $\sin x>0$ .

Recall that for any angle $\alpha$ ,

$\sin^2\alpha+\cos^2\alpha=1$

Then with the conditions determined above, we get

$\cos\theta=\sqrt{1-\left(\dfrac45\right)^2}=\dfrac35$

and

$\sin x=\sqrt{1-\left(-\dfrac5{13}\right)^2}=\dfrac{12}{13}$

Now recall the compound angle formulas:

$\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta$

$\cos(\alpha\pm\beta)=\cos\alpha\cos\beta\mp\sin\alpha\sin\beta$

$\sin2\alpha=2\sin\alpha\cos\alpha$

$\cos2\alpha=\cos^2\alpha-\sin^2\alpha$

as well as the definition of tangent:

$\tan\alpha=\dfrac{\sin\alpha}{\cos\alpha}$

Then

1. $\sin(\theta+x)=\sin\theta\cos x+\cos\theta\sin x=\dfrac{16}{65}$

2. $\cos(\theta-x)=\cos\theta\cos x+\sin\theta\sin x=\dfrac{33}{65}$

3. $\tan(\theta+x)=\dfrac{\sin(\theta+x)}{\cos(\theta+x)}=-\dfrac{16}{63}$

4. $\sin2\theta=2\sin\theta\cos\theta=\dfrac{24}{25}$

5. $\cos2x=\cos^2x-\sin^2x=-\dfrac{119}{169}$

6. $\tan2\theta=\dfrac{\sin2\theta}{\cos2\theta}=-\dfrac{24}7$

7. A bit more work required here. Recall the half-angle identities:

$\cos^2\dfrac\alpha2=\dfrac{1+\cos\alpha}2$

$\sin^2\dfrac\alpha2=\dfrac{1-\cos\alpha}2$

$\implies\tan^2\dfrac\alpha2=\dfrac{1-\cos\alpha}{1+\cos\alpha}$

Because $x$ is in quadrant II, we know that $\dfrac x2$ is in quadrant I. Specifically, we know $\dfrac\pi2$ , so $\dfrac\pi4$ . In this quadrant, we have $\tan\dfrac x2>0$ , so

$\tan\dfrac x2=\sqrt{\dfrac{1-\cos x}{1+\cos x}}=\dfrac32$

8. $\sin3\theta=\sin(\theta+2\theta)=\dfrac{44}{125}$

6 0

3 years ago

What is the answer to this<br> -11 - (-3)

BaLLatris [955]

Answer:

<u>-</u><u>8</u>

Step-by-step explanation:

-11 - (-3) =

(-11) + 3

<u>-</u><u>8</u>

5 0

1 year ago

Read 2 more answers

What is the value of x in this equation?<br> x - 1/2 = 3 1/6

Ludmilka [50]

Answer:

x= 3 2/3

Step-by-step explanation:

6 0

2 years ago

Suppose that the function fis defined on the interval (-2,2) as follows. <br>find f(-1) f(0.5) f(1)

frosja888 [35]

Answer:

Step-by-step explanation:

Hello,

-1 <= -1 < 0

so f(-1)=-1

0 <= 0.5 < 1

so f(0.5)=0

1 <= 1 < 2

so f(1)=1

Thank you.

8 0

2 years ago