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2 years ago

An atom of argon rarely bonds to an atom of another element because an argon atom has

1 answer:

5 0

The answer is (1) 8 valence electrons. Argon, being a noble gas, already possesses a full octet of valence electrons and is, therefore, very, very stable. It has an almost indomitable tendency to retain that octet. That is why it so rarely participates in any sort of bonding.

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Compound that contains a terminal carbonyl?

malfutka [58]

Many compunds have a terminal carbonyl

Aldehyde, Ketone, Carboxylic acid, Amide, Imide, Acid anhydride are the first that come to my mind.

7 0

2 years ago

What is the difference between glucose and fructose.

CaHeK987 [17]

Answer:

glucose is in large sugar molecules, while fructose is in simple fruits and vegetables

4 0

1 year ago

Read 2 more answers

What is the type of weak bond between the hydrogen of one molecule and the nitrogen of another molecule, where the two don't act

Aliun [14]

<h2>Hydrogen Bonding</h2>

Explanation:

Hydrogen bonding is a type of weak bond.
Hydrogen Bonding occurs when the hydrogen atom of one molecule is bonded with a molecule of high electronegativity element like nitrogen of another molecule.
It is a type of dipole-dipole interations.
The nitrogen is a highly electronegative element that forms a weak bond with the hydrogen atom of another molecule with dipole-dipole interaction.
Hydrogen bonds are weaker than covalent and ionic bonds.
Therefore the type of bond is Hydrogen bond.

8 0

2 years ago

What is the molar mass for 5 mol Na

zimovet [89]

Answer:

22.98977 g/

Brainliest please

4 0

2 years ago

Read 2 more answers

Hello,

nikitadnepr [17]

Answer:

$a)\ 2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3\\b)\ Decomposition\ Reaction$

Explanation:

Ferrous Sulphate $(FeSO4)$ is generally found as Lime-Green Crystals. On heating, these crystals almost immediately turn white-yellow. They then, break down to produce an anhydrous mixture of Sulphur Trioxide $(SO_3)$ , Sulphur Dioxide $(SO_2)$ as well as Ferric Oxide $(Fe_2O_3)$ .

We can hence, frame a skeletal equation of this reaction and try to balance it.

Hence,

$FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3$

Now,

a)In order to balance it through the 'Hit &Trial Method', we'll follow a series of steps:

1. First, lets compare the number of Fe (Iron) atoms on the RHS and LHS. We find that, the no. of Fe Atoms on the RHS is twice the number of Fe Atoms on the LHS. We hence, add a co-effecient 2 beside $FeSO_4$ .

2. Now, Iron atoms, Sulphur Atoms and Oxygen atoms occur 2, 2, 8 respectively on both the sides:

Hence, As all the other elements as well as iron, balance, we've arrived upon our Balanced Equation :

$2FeSO4 \xrightarrow{\text{Heat}} SO_3+SO_2+Fe_2O_3$

b) We know that, decomposition reactions are [generally] endothermic reactions in which Large Compounds decompose into smaller elements and compounds. Here, as Ferrous Sulphate decomposes into Sulphur Dioxide, Sulphur Trioxide and Ferric Oxide, the reaction that occurs here is Decomposition Reaction.

7 0

2 years ago