Looks like you have to attach a picture. It wont work, because all you did was copy it.
Let x be the width of the cardboard (which means the length of the cardboard is x+88), then the dimensions of the box are:
Length = [(x + 88) - 2(33)]
Width = x - 2(33)
Heighth = 33
Volume = length · width · heighth
144,144 = [(x + 88) - 2(33)] · [x - 2(33)] · 33
144,144 = (x+22)(x-66)(33)
4368 = (x+22)(x-66)
4368 = x² - 44x - 1452
0 = x² - 44x - 5820
use the quadratic formula to calculate that x = 101
Answer: cardboard width = 101, cardboard length = 189
If you apply the or both
Only 1 of the students would need to know the "or both", therefore maximizing the remaining amount of students you can put in.
Gerald, let's call him, knows French AND German, so there's only one less student that knows french and german. Gerald is 1 student.
MAXIMUM:
There are now 14 monolinguistic French speakers and 16 monolinguistic German's, 30 students + Gerald=31.
Minimum:
As a bonus, the minimum is 15 students knowing french AND German and only 2 monolinguistic German speakers, so 17.
Answer:
Answer; Mean = p = 0.75
Standard deviation =0.0274
Step-by-step explanation:
Mean = p = 0.75
Standard deviation = √ [ p ( 1 - p) / n ]
= √ [ 0.75 * ( 1 - 0.75) / 250]
= 0.0274
The first one would be (2x)(7) and plus the other 75 it would be 738 with that in total of it c 5 3-15