What is 6.6 repeating as a fraction

Which statement about the figure MUST be true? Select all that apply.

olga55 [171]

<h2>○=> <u>Correct options</u> :</h2><h2>□ $\color{plum}\tt\bold{(C) \: SR = 27}$ </h2><h2>□ $\color{plum}\tt\bold{(D) \: QR = 54 }$ </h2><h3><u>Steps to derive the correct options</u> :</h3>

Since two sides and one included angle is equal in △PQS and △PRS, we can conclude that they are congruent under the SAS congruence criterion.

Which means :

▪︎Angle S = Angle S

▪︎PS = PS

▪︎QS = RS

Given :

Measure of segment QS = 6n+3

Measure of segment RS = 4n+11

Thus :

$= \tt6n + 3 = 4n + 11$

$= \tt6n + 3 - 4n = 11$

$=\tt 2n + 3 = 11$

$= \tt2n = 11 - 3$

$= \tt2n = 8$

$=\tt n = \frac{8}{2}$

$\hookrightarrow\color{plum}\tt n = 4$

Thus, the value of n = 4

Measure of segment QS :

$=\tt 6n + 3$

$= \tt6 \times 4 + 3$

$= \tt24 + 3$

$\color{plum}\tt \: \bold{QS = 6n + 3 = \tt\bold{27}}$

Thus, measure of QS = 27

Measure of RS :

$=\tt 4n + 11$

$=\tt 4 × 4 + 11$

$=\tt 16+11$

$\color{plum}\tt \: \bold{RS = 4n + 11 = \tt\bold{27}}$

Measure of QR :

$=\tt 27+27$

$\color{plum}\tt \: \bold{QR = 27+27 \tt\bold{=54}}$

Thus :

▪︎QS = 27

▪︎RS = 27

▪︎QR = 54

Therefore, the correct options are :

▪︎(C) SR = 27

▪︎(D) QR = 54

7 0

2 years ago

A polygon has 7 sides. What is the sum of the measure of the exterior angles of the polygon?

Mariulka [41]

I think it's C, 360 degrees.

5 0

2 years ago

Read 2 more answers

A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team. How many diff

lys-0071 [83]

Answer:

The team can be formed in 756 different ways

Step-by-step explanation:

This is a combination problem since we are to select a set of people from a group. Combination has to do with selection.

for example, if r number of object is to be selected from a pool of n objects, this can be done in nCr number of ways.

$nCr = \frac{n!}{(n-r)!r!}$

Now If A company has 7 male and 9 female employees, and needs to nominate 2 men and 2 women for the company bowling team, then this can be done in the following way;

$7C2 * 9C2$

$7C2 = \frac{7!}{5!2!} \\= \frac{7*6*5!}{5!*2} \\= 7*3\\= 21ways\\\\similarly;\\\\9C2 = \frac{9!}{7!2!}\\9C2= \frac{9*8*7!}{7!*2} \\9C2 = 9*4\\9C2 = 36$